syntax: break closures are implicitly ended with 'break'

[nit.git] / tests / base_closure_break_default2.nit

diff --git a/tests/base_closure_break_default2.nit b/tests/base_closure_break_default2.nit
new file mode 100644 (file)
index 0000000..174cc23
--- /dev/null
+++ b/tests/base_closure_break_default2.nit
@@ -0,0 +1,46 @@
+# This file is part of NIT ( http://www.nitlanguage.org ).
+#
+# Copyright 2009 Jean Privat <jean@pryen.org>
+#
+# Licensed under the Apache License, Version 2.0 (the "License");
+# you may not use this file except in compliance with the License.
+# You may obtain a copy of the License at
+#
+#     http://www.apache.org/licenses/LICENSE-2.0
+#
+# Unless required by applicable law or agreed to in writing, software
+# distributed under the License is distributed on an "AS IS" BASIS,
+# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+# See the License for the specific language governing permissions and
+# limitations under the License.
+
+import kernel
+
+class A
+       fun foo: Int
+               break !bar do
+                       #alt1# return
+                       #alt2# return 1
+                       #alt3# abort
+                       #alt4# continue
+                       #alt5# continue 20
+                       #alt6# break
+                       #alt7# break 1
+                       #alt8# break 'x'
+                       break 20#!alt9#
+               end
+       do
+               1.output
+               bar
+               3.output
+       end
+end
+
+var a = new A
+0.output
+var x = a.foo !bar do break 2
+x.output
+0.output
+x = a.foo
+x.output
+0.output