# Construct the current partitionning
	#
	#     var s = new DisjointSet[Int]
	#     s.add_all([1,2,3,4,5,6])
	#     s.union(1,2)
	#     s.union(1,3)
	#     s.union(4,5)
	#     var p = s.to_partitions
	#     assert p.length == 3
	fun to_partitions: Collection[Set[E]]
	do
		return to_subpartition(self)
	end