ordered_tree: remove subs when all children are detached.
[nit.git] / lib / ordered_tree.nit
1 # This file is part of NIT ( http://www.nitlanguage.org ).
2 #
3 # Copyright 2012 Jean Privat <jean@pryen.org>
4 #
5 # Licensed under the Apache License, Version 2.0 (the "License");
6 # you may not use this file except in compliance with the License.
7 # You may obtain a copy of the License at
8 #
9 # http://www.apache.org/licenses/LICENSE-2.0
10 #
11 # Unless required by applicable law or agreed to in writing, software
12 # distributed under the License is distributed on an "AS IS" BASIS,
13 # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
14 # See the License for the specific language governing permissions and
15 # limitations under the License.
16
17 # Manipulation and presentation of ordered trees.
18 module ordered_tree
19
20 # Generic structure to manage and display an ordered tree
21 #
22 # Ordered tree are tree where the elements of a same parent are in a specific order
23 #
24 # Elements of the trees are added with the `add` method that takes a parent and
25 # a sub-element.
26 # If the parent is `null`, then the element is considered a root.
27 #
28 # ~~~~
29 # var t = new OrderedTree[String]
30 # t.add(null, "root")
31 # t.add("root", "child1")
32 # t.add("root", "child2")
33 # t.add("child1", "grand-child")
34 # assert t.length == 4
35 # ~~~~
36 #
37 # By default, the elements with a same parent
38 # are visited in the order they are added.
39 #
40 # ~~~
41 # assert t.to_a == ["root", "child1", "grand-child", "child2"]
42 # assert t.write_to_string == """
43 # root
44 # |--child1
45 # | `--grand-child
46 # `--child2
47 # """
48 # ~~~
49 #
50 # The `sort_with` method can be used reorder elements
51 #
52 # ~~~
53 # t.add("root", "aaa")
54 # assert t.to_a == ["root", "child1", "grand-child", "child2", "aaa"]
55 # t.sort_with(alpha_comparator)
56 # assert t.to_a == ["root", "aaa", "child1", "grand-child", "child2"]
57 # ~~~
58 #
59 # This class can be used as it to work with generic trees but can also be specialized to provide more specific
60 # behavior or display. It is why the internal attributes are mutable.
61 class OrderedTree[E: Object]
62 super Writable
63 super Collection[E]
64 super Cloneable
65
66 # The roots of the tree (in sequence)
67 var roots = new Array[E]
68
69 # The branches of the trees.
70 # For each element, the ordered array of its direct sub-elements.
71 var sub = new HashMap[E, Array[E]]
72
73 # The parent of each element.
74 #
75 # Roots have `null` as parent.
76 private var parents = new HashMap[E, nullable E]
77
78 redef fun length do return parents.length
79
80 redef fun has(e) do return parents.has_key(e)
81
82 # The parent of the element `e`
83 #
84 # Roots have `null` as parent.
85 #
86 # ~~~
87 # var tree = new OrderedTree[Int]
88 # tree.add(1, 2)
89 # assert tree.parent(2) == 1
90 # assert tree.parent(1) == null
91 # ~~~
92 fun parent(e: E): nullable E do return parents[e]
93
94 # Add a new element `e` in the tree.
95 #
96 # `p` is the parent of `e`.
97 # If `p` is null, then `e` is a root element.
98 #
99 # If `e` is already in the tree, it is detached from its old
100 # parent and attached to the new parent `p`.
101 fun add(p: nullable E, e: E)
102 do
103 detach(e)
104 parents[e] = p
105 if p == null then
106 roots.add(e)
107 else
108 if not has(p) then add(null, p)
109 if sub.has_key(p) then
110 sub[p].add(e)
111 else
112 sub[p] = [e]
113 end
114 end
115 end
116
117 # Append all nodes `es` as children of `p`.
118 fun add_all(p: nullable E, es: Collection[E])
119 do
120 for e in es do add(p, e)
121 end
122
123 # Temporary remove `e`.
124 #
125 # Children of `e` are left untouched in the tree.
126 # This make the tree inconstant until `e` is added back.
127 private fun detach(e: E)
128 do
129 var old_parent = parents.get_or_null(e)
130 if old_parent != null then
131 var subs = sub[old_parent]
132 subs.remove(e)
133 if subs.is_empty then
134 # remove the sub when all children are detached
135 # so that `==` and `hash` are sane
136 # Otherwise an empty array will be considered
137 # differently than no array.
138 sub.keys.remove(old_parent)
139 end
140 else if roots.has(e) then
141 roots.remove(e)
142 end
143 end
144
145 # print the full tree on `o`
146 # Write a ASCII-style tree and use the `display` method to label elements
147 redef fun write_to(stream: Writer)
148 do
149 for r in roots do
150 stream.write display(r)
151 stream.write "\n"
152 sub_write_to(stream, r, "")
153 end
154 end
155
156 private fun sub_write_to(o: Writer, e: E, prefix: String)
157 do
158 if not sub.has_key(e) then return
159 var subs = sub[e]
160 if subs.is_empty then return
161 var last = subs.last
162 for e2 in subs do
163 if e2 != last then
164 o.write "{prefix}|--{display(e2)}\n"
165 sub_write_to(o, e2, prefix+"| ")
166 else
167 o.write "{prefix}`--{display(e2)}\n"
168 sub_write_to(o, e2, prefix+" ")
169 end
170 end
171 end
172
173 # Sort roots and other elements using a comparator method
174 # This method basically sorts roots then each group of children
175 fun sort_with(comparator: Comparator)
176 do
177 comparator.sort(roots)
178 for a in sub.values do
179 comparator.sort(a)
180 end
181 end
182
183 # How to display a specific element of the tree
184 # By defaut, uses `to_s`
185 #
186 # Subclasses should redefine this method to provide a specific output
187 fun display(e: E): String do return e.to_s
188
189 # Get an array of the contained elements
190 # Order is preserved
191 #
192 # var tree = new OrderedTree[Int]
193 # tree.add_all(null, [1, 2])
194 # tree.add_all(1, [11, 12])
195 # tree.add_all(11, [111, 112])
196 # tree.add_all(12, [121, 122])
197 # tree.add_all(2, [21, 22])
198 # assert tree.to_a == [1, 11, 111, 112, 12, 121, 122, 2, 21, 22]
199 redef fun to_a: Array[E] do
200 var res = new Array[E]
201 for r in roots do sub_to_a(r, res)
202 return res
203 end
204
205 private fun sub_to_a(e: E, res: Array[E]) do
206 res.add e
207 if sub.has_key(e) then for e2 in sub[e] do sub_to_a(e2, res)
208 end
209
210 # var tree = new OrderedTree[Int]
211 # assert tree.is_empty
212 # tree.add(null, 1)
213 # assert not tree.is_empty
214 redef fun is_empty: Bool do return roots.is_empty
215
216 # var tree = new OrderedTree[Int]
217 # tree.add(null, 1)
218 # tree.add(1, 11)
219 # assert tree.first == 1
220 redef fun first do return roots.first
221
222 # var tree = new OrderedTree[Int]
223 # tree.add_all(null, [1, 2])
224 # tree.add_all(1, [11, 12])
225 # tree.add_all(11, [111, 112])
226 # tree.add_all(12, [121, 122])
227 # tree.add_all(2, [21, 22])
228 # var order = [1, 11, 111, 112, 12, 121, 122, 2, 21, 22]
229 # assert tree.iterator.to_a == order
230 redef fun iterator do return new OrderedTreeIterator[E](self)
231
232 # Two trees are equal if they have the same nodes in the same order
233 #
234 # ~~~
235 # var t1 = new OrderedTree[Int]
236 # t1.add_all(null, [1, 2])
237 # t1.add_all(1, [11, 12])
238 #
239 # var t2 = new OrderedTree[Int]
240 # t2.add_all(null, [1, 2])
241 #
242 # assert t1 != t2
243 #
244 # t2.add_all(1, [11, 12])
245 #
246 # assert t1 == t2
247 # ~~~
248 redef fun ==(other)
249 do
250 if not other isa OrderedTree[Object] then return false
251 return roots == other.roots and sub == other.sub
252 end
253
254 redef fun hash
255 do
256 return roots.hash + sub.hash
257 end
258
259 # Shallow clone of the tree.
260 #
261 # ~~~
262 # var t = new OrderedTree[Int]
263 # t.add_all(null, [1, 2])
264 # t.add_all(1, [11, 12])
265 #
266 # assert t.clone == t
267 # ~~~
268 redef fun clone
269 do
270 var res = new OrderedTree[E]
271 res.add_all(null, roots)
272 for p, es in sub do
273 res.add_all(p, es)
274 end
275 return res
276 end
277 end
278
279 # An Iterator over an OrderedTree
280 private class OrderedTreeIterator[E: Object]
281 super Iterator[E]
282
283 var tree: OrderedTree[E]
284
285 var iterators = new Array[Iterator[E]]
286
287 init do
288 if not tree.is_empty then
289 iterators.add tree.roots.iterator
290 end
291 end
292
293 redef fun is_ok do return not iterators.is_empty
294
295 redef fun item do
296 assert is_ok
297 return iterators.last.item
298 end
299
300 redef fun next do
301 assert is_ok
302 if tree.sub.has_key(item) then
303 iterators.add tree.sub[item].iterator
304 else
305 iterators.last.next
306 while is_ok and not iterators.last.is_ok do
307 iterators.pop
308 if is_ok and iterators.last.is_ok then
309 iterators.last.next
310 end
311 end
312 end
313 end
314
315 redef fun iterator do return new OrderedTreeIterator[E](tree)
316 end